Can someone explain me this : I did not get this statement : "For every two chunks of data, we need one parity block, so the storage overhead is 50% (Figure 2)". But the image we have used 4 chunks to create one P1 and P2 respectively
Erasure coding can be implemented in various ways depending on the specific application and desired level of protection. Some of the commonly used algorithms are
Can someone explain me this : I did not get this statement : "For every two chunks of data, we need one parity block, so the storage overhead is 50% (Figure 2)". But the image we have used 4 chunks to create one P1 and P2 respectively
What’s a real time example of this?
Erasure coding can be implemented in various ways depending on the specific application and desired level of protection. Some of the commonly used algorithms are
- Rabin's Information Dispersal Algorithm
- Reed-Solomon codes
RAID 5 storage configuration uses erasure coding.